python - Syntax errors when using tkinter -

-

i have imported tkinter @ beginning of code , below have @ end gui. worked fine gui running , buttons displaying until wrote code 'strengthskill' , getting sytax error @ beginning of line:

mlabel=label(text='battle!!').place(x=50,y=130)

it highlighting "mlabel" error have looked , can't see problem is. have created second version tkinter stripped out , works fine. 

mgui = tk()    ment = diceint()      mgui.geometry('400x400')    mgui.configure(bg="purple")    mgui.title('miss watts dice games')      mlabel=label(text='4,6,12 sided dice roller').place(x=50,y=50)    mbutton=button(mgui,text="go",command=diceroll).place(x=250,y=50)    mentry=entry(mgui,variable=ment).pack()     mlabel=label(text='strength , skill calculator').place(x=50,y=90)    mbutton=button(mgui,text="go",command=strengthskill.place(x=250,y=90)     mlabel=label(text='battle!!').place(x=50,y=130)    mbutton=button(mgui,text="go",command=battle.place(x=250,y=130)      mbutton=button(mgui,text="exit",command=close).place (x=50,y=250)     mlabel=label(text='\n{copyright sign} dru watts 2014').place(x=50,y=300)     mgui.mainloop()

unfortunately can't post main part of code creating example show students of controlled assessment coursework need complete , i'd rather didn't find this!

please gentle - new tkinter. worried may have mixed tutorials bit much!

you missing closing parenthesis here:

mbutton=button(mgui,text="go",command=strengthskill).place(x=250,y=90)                                                    ^

and here:

mbutton=button(mgui,text="go",command=battle).place(x=250,y=130)                                             ^

also, because place , pack methods of every tkinter widget work in-place,mbutton, mlabel, etc. assigned none. thus, if plan use these variables later on, need call these methods on own lines:

mlabel=label(text='4,6,12 sided dice roller') mlabel.place(x=50,y=50)

otherwise, recommend removing variables altogether because unnecessary:

label(text='4,6,12 sided dice roller').place(x=50,y=50) button(mgui,text="go",command=diceroll).place(x=250,y=50) entry(mgui,variable=ment).pack()

Comments

Post a Comment

Popular posts from this blog

c++ - OpenCV Error: Assertion failed <scn == 3 ::scn == 4> in unknown function, -

-
i read alot other solution still confused should mine... #include <opencv2/objdetect/objdetect.hpp> #include <opencv2/highgui/highgui.hpp> #include <opencv2/imgproc/imgproc.hpp> #include <iostream> #include <stdio.h> using namespace std; using namespace cv; int main(int argc, const char** argv) { //create cascade classifier object used face detection cascadeclassifier face_cascade; //use haarcascade_frontalface_alt.xml library face_cascade.load("haarcascade_frontalface_alt.xml"); //setup video capture device , link first capture device videocapture capturedevice; capturedevice.open(0); //setup image files used in capture process mat captureframe; mat grayscaleframe; //create window present results namedwindow("outputcapture", 1); //create loop capture , find faces while (true) { //capture new image frame capturedevice >> captureframe; ...
Read more

php - render data via PDO::FETCH_FUNC vs loop -

-
i've been using 2 methods render data. the first one: function name($id,$name){ return '<div id="'.$id.'">'.$name.'</div>'; } echo implode($pdo->query("select id,name user")->fetchall(pdo::fetch_func,'name')); the second one: $users = $pdo->query("select id,name user")->fetchall(pdo::fetch_obj); foreach($users $user){ echo name($user->id,$user->name); } i don't understand how pdo::fetch_func works. tried figure out. however, not well-documented. could please explain fetch mode? , also, 1 performs better? thank you. both methods wrong , have learn how use templates , how separate business logic presentation logic. $users = $pdo->query("select id,name user")->fetchall(pdo::fetch_obj); tpl::assign('users', $users); is code business logic part. then in template <?php foreach $users $row): ?> <div id="<?=$...
Read more

The canvas has been tainted by cross-origin data in chrome only -

-
uncaught securityerror: failed execute 'getimagedata' on 'canvasrenderingcontext2d': canvas has been tainted cross-origin data i getting above error in chrome. code(following) works fine in mozilla. have not corss domain issue. why above error in chrome? var wheel_canvas, wheel_context, can_w, can_h, wheel_grd; var large_radius = 160; var small_radius = 120; var wheel_canvas = document.getelementbyid('wheel_canvas'); var wheel_context = wheel_canvas.getcontext('2d'); var can_w = $(wheel_canvas).width(); var can_h = $(wheel_canvas).height(); var centerx = can_w / 2, centery = can_h / 2; var wheel_grd = null; test('#ff0000'); function test(hex) { $('#clrpicker').css({'left': 210, 'top': 210 }); inverted = hexbw(hex); $('#color_val_show').val(hex); current_color_hex_val_selected = hex; $('#color_val_show').css({'color':inverted,'background':hex}); fillgradient...
Read more