How to use negative regex matching with grep -E? -

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this question has answer here:

i'm using following regex via grep -e match specific string of chars via | pipe.

$ git log <more switches here> | grep -e "match me"

output:

match me once match me twice

what i'm looking negative match (return output lines don't contain specified string following grep doesn't it:

$ git log <more switches here> | grep -e "^match me"

desired output:

whatever 1 whatever 2

here full output comes command line:

match me once match me twice whatever 1 whatever 2

how arrive @ desired output per negative regex match?

use -v option inverts matches, selecting non-matching lines

grep -v 'match me'

another option use -p interprets pattern perl regular expression.

grep -p '^((?!match me).)*$'

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