vim - Get the length of the string in substitution -

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i'd calculate length of replace string used in substitution. is, "bar" in :s/foo/bar. suppose have access command string, can run , undo it, , may separate parts marked / split(). how string length of replace string if contains special characters \1, \2 etc or ~?

for instance if have

:s/\v(foo)|(bars)/\2\rreplace/

the replace length strlen("bars\rreplace") = 12.

edit: clear, hope use move cursor past text affected substitute operation. i'd appreciate alternative solutions well.

you have use :help sub-replace-expression. in it, use submatch(2) instead of \2. if expression custom function, can side effect store original length in variable, , access later:

function! replace()     let g:replacelength = strlen(submatch(0))     " equivalent of \2\rreplace     return submatch(2) . "\r" . 'replace' endfunction  :s/\v(foo)|(bars)/\=replace()/

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