regex - HOW TO EXTRACT LIST 1 FROM LIST2 in Bash/Unix? -

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i have 2 list. need extract rows have first list row elements second list. looking right syntax read 1 list , other , extract list 1 2 based on regex. looking exact text match. output include whole row list2 well. thanks.

list 1 in text file:

abc efg hij klm

list 2 in text file:

tttt;kkkkkkk;ooooo;efg dalfjkhd;hij;ppp gsfdhgjh;fhajdjfkasljk;abc;asdkfhjaskabc;fa;lkdja abc;hhhhh;llll dddd;lllll ppppppppp:rrrrrrrrrradjkfjadl;fireuqwoepiruqwepiormvndfkgjs; hflahflakjdfhalksdfhfjaoeirfjaklf;sdfgsfgs

desired output..the text in list 1 found ..space , row found in list 2.:

efg tttt;kkkkkkk;ooooo;efg hij dalfjkhd;hij;ppp abc gsfdhgjh;fhajdjfkasljk;abc;asdkfhjaskabc;fa;lkdja abc abc;hhhhh;llll

try grep -f

grep -f list1 list2

man grep

-f file, --file=file

read 1 or more newline separated patterns file. empty pattern lines match every input line. newlines not considered part of pattern. if file empty, nothing matched.

edit: example of grep -f in action

$ cat list1 abc efg hij klm  $ cat list2 tttt;kkkkkkk;ooooo;efg dalfjkhd;hij;ppp gsfdhgjh;fhajdjfkasljk;abc;asdkfhjaskabc;fa;lkdja abc;hhhhh;llll dddd;lllll ppppppppp:rrrrrrrrrradjkfjadl;fireuqwoepiruqwepiormvndfkgjs; hflahflakjdfhalksdfhfjaoeirfjaklf;sdfgsfgs  $ grep -f list1 list2 tttt;kkkkkkk;ooooo;efg dalfjkhd;hij;ppp gsfdhgjh;fhajdjfkasljk;abc;asdkfhjaskabc;fa;lkdja abc;hhhhh;llll

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