escaping - How to Print An Odd Number of Backslashes in Python -

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i need print string part of list has 3 backslashes in in python. however, not appearing simple expected.

print ["\\\"]  traceback (most recent call last):   file "<string>", line 1, in <fragment>  eol while scanning string literal: <string>, line 1, pos 13

any string has odd number of backslashes because python escaping quote. tried escaping myself:

print ["\\\\\\"] ['\\\\\\']

which 6 backslashes. not wanted. has stumped few of around water cooler.

'\\\\\\' string contain 3 backslashes. can see there 3 characters in string applying list it:

in [166]: list('\\\\\\') out[166]: ['\\', '\\', '\\']

'\\'*3 work:

in [167]: list('\\'*3) out[167]: ['\\', '\\', '\\']

or since 

in [169]: hex(ord('\\')) out[169]: '0x5c'

you avoid need escape backslash using \x5c:

in [170]: print('\x5c\x5c\x5c') \\\

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