javascript - jQuery - How to select last column of all rows in a table? -

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assuming have html table follows (with appropriate tr, td tags):

a1 | b1 | c1 a2 | b2 | c2 a3 | b3 | c3 a4 | b4 | c4  <table border="1"> <tr>     <td>a1</td>     <td>b1</td>     <td>c1</td> </tr> <tr>     <td>a2</td>     <td>b2</td>     <td>c2</td> </tr> <tr>     <td>a3</td>     <td>b3</td>     <td>c3</td> </tr> <tr>     <td>a4</td>     <td>b4</td>     <td>c4</td> </tr> </table>

i'm trying select c* rows perform action on them.

using $('td:last') selector selects last td tag, i.e., c4.

i tried $('tr > td:last') didn't work. correct selector in case?

:last jquery selector, select very last element of type. you're looking :last-child.

similarly, td:first-child first cell, while :first gets first element of type.

here's fiddle @ 4 examples.


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