xml - How do I create a content node based on different conditions, using xsl:if-else? -

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right now, i'm creating following node based off text of headerlistimport div. 

<content name="importbizpartner">   <xsl:value-of select="//div[@class='headerlistimport']/a/text()" /> </content>

the problem text node empty. in case, want contents of node 'no name available'.

i know, should know how this, i'm drawing blank. application allows me use xsl:if-else, i'm not sure of sytax. appreciated.

you should go xsl:choose, xslt doesn't have xsl:if-else element:

<content name="importbizpartner">     <xsl:choose>         <xsl:when test="not(//div[@class='headerlistimport']/a/text())">             <xsl:value-of select="//div[@class='headerlistimport']/a/text()" />         </xsl:when>         <xsl:otherwise>             no data available         </xsl:otherwise>     </xsl:choose> </content>

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