bash - Single-quote part of a line using sed or awk -

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convert input text follows, using sed or awk:

input file:

       113259740 qa test in progress        219919630 uat test in progress

expected output:

       113259740 'qa test in progress'        219919630 'uat test in progress'

you try gnu sed command also,

sed -r "s/^( +) ([0-9]+) (.*)$/\1 \2 '\3'/g" file

  • ^( +), catches 1 or more spaces @ starting , stored in group(1).

  • ([0-9]+) - after catching 1 or more spaces @ starting, next matches space after , fetch numbers next space store in group(2).

  • (.*)$ - fetch characters next numbers upto last character , store in group(3).

  • all fetched groups rearranged in replacement part according desired output.

example:

$ cat ccc        113259740 qa test in progress        219919630 uat test in progress  $ sed -r "s/^( +) ([0-9]+) (.*)$/\1 \2 '\3'/g" ccc        113259740 'qa test in progress'        219919630 'uat test in progress'

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