haskell - apply a list of functions to a value one after another -

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this question has answer here:

is there built in function apply list of functions value 1 after another? using this, seems quite inelegant me.

-- applyfunctions [(*2), (+3), (*4)] 1 == ((1 * 2) + 3 ) * 4 applyfunctions :: [(a -> a)] -> -> applyfunctions [] x = x applyfunctions [f] x = f x applyfunctions (f:fs) x = applyfunctions fs (f x)

you can use foldl (flip ($))

foldl (flip ($)) 1 [(*2), (*3), (*4)] --yields 24

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