printwriter - Hiding headers from a query in java program -

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so have program spits out data google csv file. want allow users choose display headers or not via using string.

here printer:

...some code     // getting queries print     if (results.getrows() == null || results.getrows().isempty()) {         pw.println("no results found.");         system.out.println("no results found.");     } else {      // print column headers.        (columnheaders header : results.getcolumnheaders()) {           pw.print(header.getname() + ", ");       }       pw.println();       // print actual data.      (list<string> row : results.getrows()) {        (string column : row) {          pw.print(column + ",");        }        pw.println();      }       pw.close();    }  } }

i have properties file connected program , want put when user types in no in header part of properties file dont want headers show.

i thinking converting header part string , putting in if statement. suggestions? thx in advanced

edit:

// column headers statement      if (headers=="yes") {          (columnheaders header : results.getcolumnheaders())               pw.print(header.getname() + ", ");     } else {     // print column headers.     (columnheaders header : results.getcolumnheaders()) {         pw.print("" + ", ");     }     pw.println();   }   // getting queries print     if (results.getrows() == null || results.getrows().isempty()) {         pw.println("no results found.");         system.out.println("no results found.");     } else {       // print actual data.      (list<string> row : results.getrows()) {        (string column : row) {          pw.print(column + ",");        }        pw.println();      }       pw.close();    }   }    }

but have not working correctly.

first thing first, not checking user input correctly match

you need change

if (headers=="yes") {

to

if (headers.equals("yes")) {

i rid of else statement printing out nothing in first row except commas. want first row commas?

make sure close stream @ end no matter what, too. looks pw.close() in else statement.


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