mysql - Need to SUM All Rows by a Non-Numeric Condition AND a GROUP BY -

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i have table contains condition need test , total group total of number of groups equal value.

example:

  • group 1 total of conditions = 1
  • group 2 total of conditions = 14
  • group 3 total of conditions = 5
  • group 4 total of conditions = 1

etc.

i need calculate total of each group total groups = 1

this base code have come basic group totals. (i'm using sum(if(condition = true,1,0)) in effort build query can used subquery):

select sum(if(`condition` <> '' , `condition` not null,1,0)) totalerrors  site_analytics  group fourid;

of course same as:

select count(*) totalerrors  site_analytics  group fourid  `condition` <> '' , `condition` not null;

returns row each group group total. need group groups group total.

either way need number of groups (fourid) = 1 (or 2,3,4 etc)

the end result i'm looking generate report has number of groups = 1, 2,3,4,5,5+

i have tried using above queries sub-queries no success such as:

select  sum((select sum(if(`condition` <> '' , `condition` not null,1,0)) site_analytics group fourid) `siteswith1error` sitelog_master;

this query used getting other totals similar report:

select  (select count(`fourid`) sitelog_master) `totalsites`, (select count(`condition`) site_analytics (`condition` <> '' , `condition` not null)) `totalfieldswitherrors`, (select count(distinct m.fourid) sitelog_master m left join site_analytics using (fourid) (`condition` null or `condition` <> '')) `totalsiteswitherrors`, (select count(`condition`) site_analytics `condition` '%required%') `totalmissingrequiredfields`, (select count(distinct `condition`) site_analytics (`condition` <> '' , `condition` not null)) `totaluniquetypesoferrors` sitelog_master limit 1;

this came with. moved sub-query clause instead of trying in select clause:

select sum(t.totalerrors) (select sum(if(`condition` <> '' , `condition` not null,1,0)) totalerrors site_a nalytics group fourid having totalerrors = 1) t;

the sub-query returns 45 rows sum in select clause sums single row.

to add remaining breakouts need. if() in select clause sum , remove having from clause can create other summed totals:

    select      sum(if(t.totalerrors = 1,1,0)) group1,      sum(if(t.totalerrors = 2,1,0)) group2,      sum(if(t.totalerrors = 3,1,0)) group3,      sum(if(t.totalerrors = 4,1,0)) group4,      sum(if(t.totalerrors >= 5,1,0)) group5       (select sum(if(`condition` <> '' , `condition` not null,1,0))  totalerrors site_analytics group fourid) t;

returns:

group1 45
group2 76
group3 90
group4 57
group5+ 360


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